x^2+5x+54=180

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Solution for x^2+5x+54=180 equation:



x^2+5x+54=180
We move all terms to the left:
x^2+5x+54-(180)=0
We add all the numbers together, and all the variables
x^2+5x-126=0
a = 1; b = 5; c = -126;
Δ = b2-4ac
Δ = 52-4·1·(-126)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-23}{2*1}=\frac{-28}{2} =-14 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+23}{2*1}=\frac{18}{2} =9 $

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